Some simple derivations with some simple formulas.

U:     Volt (V)
I :       Amp.
P:      Watt
W:      Joule
t:        Second (time)
C:      Farad (F)
Q:     Coulomb

P  = U * I  [1]
W = P * t  [2]
Q  = C * U   [3]
W = 0.5 * C * U * U [4]
Q = I * t   [5]

[1] and [2] --->   W = U * I * t  [6]
[4] and [6] --->   0.5 * C * U * U = U * I * t      ---> 0.5 * C * U = I * t [7]
[3]               --->  C = Q / U  [8]
[7] and [8] --->  0.5 * Q / U * U = I * t              ---> Q = 2 * I * t  [9]
[5] and [9] --->  I * t = 2 * I * t                           ---> 1 = 2
 

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Yes, actually  1= 1 because the formula [5] Q = I * t does not apply for capacitor as I is not constant when charging or discharging. This formula can be used for electrolysis for ex. These formulas were from the same basic textbook.

But  another question please:
How much is 1 Q + 1 Q ?


Answer n° 1

SO

1 Q + 1 Q  = 2 Q


Answer n° 2

SO

1 Q + 1 Q  = 1 Q


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